Flag Electrostatics> hc verma...
question mark

Two identical balls are charged by rubbing against each other.They are suspended from a horizontal rod through two stringsof lenghts 20cm each the separation between the suspended points being 5cm.In equilibriumthe separation between the balls is 3cm.find the mass of each ball and tension in the string.the charge on each ball is 0.000000002C (WITH MAGNITUDE).

chinthalapudi prashanth , 14 Years ago
Grade 11
anser 2 Answers
Askiitians Expert Soumyajit IIT-Kharagpur

Last Activity: 14 Years ago

Dear Chinthalapudi Prashanth,

Ans Let the strings make an angle θ with the vertical

then Tcosθ=mg.............(1)

  Tsinθ=K q²/r²...............(2)

Dividing 2 by 1 we get

tanθ=Kq²/mgr²

Solving we get,

m=8×10^-5 Kg. each

N.B: You can also solve it by using moment equations TRY IT.

Please feel free to post as many doubts on our discussion forum as you can. If you find any question
Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We
are all IITians and here to help you in your IIT JEE preparation.


All the best Chinthalapudi Prashant!!!

 


Regards,

Askiitians Experts
Soumyajit Das IIT Kharagpur

ayush aggarwal

Last Activity: 14 Years ago

answer posted by everyone is right but try to solve this problem using lamis theorem . it is the shortest and the best way to solve this

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...