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A totl charge Q is broken in two parths Q1 and Q2 and they are placed at a distance R from each other the maximum force of repulsion between them will occur when
Dear pallavi
let parts are sepereted at a distance of d
Q=q1+q2 (conservation of charge)
so repulsion force F= k Q1(Q2)/d2
k Q1(Q-Q1)/d2
here Q and d are constant so for maximum force differentiate the force w.r.t Q1
dF/dQ1 = k/d2 [Q -2Q1]
for maximum force dF/dQ1=0
Q-2Q1=0
Q1 +Q2 -2Q1 =0
Q1 =Q2
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