Two copper balls each weighining 10g are kept in air 1 cm apart If one electron from every 10^6 atoms is transfered from one ball to the other the coloumb force between them is

Question

Badiuddin askIITians.ismu Expert · Answer

Dear pallavi

molecular weight = 63.55

so mass of 1 mole of cu is =63.55

in 63.55 g number of cu atom = 6.022 X 10²³

in 10 g number of cu atom = 10*6.022/63.55 X 10²³ =1.00 X 10 ²³

number of electron tranfered = 10 ²³/ 10⁶

=10¹⁷

so charged genereted in one ball is q =1.6 X 10^-19 X 10¹⁷

=1.6 X 10^-2 C

so force F = 1/4∏ε qq/r²

=9 X 10⁹ * (1.6 X 10^-2 )² / 10-⁴

=2.304 10¹⁰ N

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Kushagra Madhukar · Answer

Dear student, Please find the attached solution to your problem below. molecular weight = 63.55 so mass of 1 mole of cu is =63.55 in 63.55 g number of cu atom = 6.022 X 10 23 in 10 g number of cu atom = 10*6.022/63.55 X 10 23 =1.00 X 10 23 number of electron tranfered = 10 23 / 10 6 = 10 17 so charged genereted in one ball is q =1.6 X 10 -19 X 10 17 =1.6 X 10 -2 C so force F = 1/4∏ε qq/r 2 =9 X 10 9 * (1.6 X 10 -2 ) 2 / 10- 4 =2.304 10 10 N Thanks and regards, Kushagra

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Two copper balls each weighining 10g are kept in air 1 cm apart If one electron from every 10^6 atoms is transfered from one ball to the other the coloumb force between them is

Two copper balls each weighining 10g are kept in air 1 cm apart If one electron from every 10^6 atoms is transfered from one ball to the other the coloumb force between them is

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