Two copper balls each weighining 10g are kept in air 1 cm apart If one electron from every 10^6 atoms is transfered from one ball to the other the coloumb force between them is

Dear pallavi

molecular weight = 63.55

so mass of 1 mole of cu is =63.55

 in 63.55 g number of cu atom   = 6.022 X 10²³ 

 in 10 g number of cu atom   = 10*6.022/63.55  X 10²³ =1.00 X 10 ²³

  number of electron tranfered  = 10 ²³   / 10⁶

                                             =10¹⁷

so charged genereted in one ball is q  =1.6 X 10^-19  X 10¹⁷

                                                   =1.6 X 10^-2 C

so force F = 1/4∏ε qq/r²

              =9 X 10⁹ * (1.6 X 10^-2 )² / 10-⁴

              =2.304 10¹⁰ N

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