Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

WHILE DERIVING THE FORMULA FOR THE POTENTIAL ENERGY AT A POINT DUE TO POINT CHARGE WE MULTIPLY THE FORCE ON THE TEST CHARGE DUE TO THE POINT CHARGE(AT THE INITIAL POSITION)WITH A SMALL DISTANCE dR AND THEN INTEGRATE IT TO FIND THE TOTAL POTENTIAL ENERGY.wHY DO WE TAKE THE SAME INITIAL FORCE ON THE PARTICLE WHEN WE KNOW THAT AT A DIFFERENT POSITION THE FORCE WILL BE DIFFERENT?(INFACT FORCE WILL DIFFER EVEN WITH A SMALL DISPLACEMENT)

WHILE DERIVING THE FORMULA FOR  THE POTENTIAL ENERGY AT A POINT DUE TO POINT CHARGE


WE MULTIPLY THE FORCE ON THE TEST CHARGE DUE TO THE POINT CHARGE(AT THE INITIAL POSITION)WITH A SMALL DISTANCE dR AND THEN INTEGRATE IT TO FIND THE TOTAL POTENTIAL ENERGY.wHY DO WE TAKE THE SAME INITIAL FORCE ON THE PARTICLE WHEN WE KNOW THAT AT A DIFFERENT POSITION THE FORCE WILL BE DIFFERENT?(INFACT FORCE WILL DIFFER EVEN WITH A SMALL DISPLACEMENT)

Grade:11

1 Answers

Badiuddin askIITians.ismu Expert
147 Points
11 years ago

Dear anshuman

force is not constant .

we are taking F=q1q2/4∏ε r

force is dependent on r

if we perform intigration then for different value of limit r is different and thus force is different.

Please feel free to post as many doubts on our discussion forum as you can.
 If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.
 We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.

 All the best.
 
Regards,
Askiitians Experts
Badiuddin

 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free