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the charge per unit length of the four quadrant of the ring is 2a,-2a,a and a respectively. the electric field at the centre with direction is?

sagar singh , 11 Years ago
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anser 1 Answers
Sher Mohammad

Last Activity: 10 Years ago

2a and a are in opposite direction so equivalant of these two 2ka/r*sqrt(2) in 3rd quadrant

that is (-)2ka/r*sqrt(2)(1/sqrt(2) i +1/sqrt(2) j)

resultant of -2a and a is 6ka/r*sqrt(2)(1/sqrt(2) i -1/sqrt(2) j)
so resultant is 2ka/r i -4ka/r j

Sher Mohammad
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