0

Guest

Courses New

(1) What is the excess number of electrons that must be placed on each of two small sphere spaced 3cm apart so that a force of repulsion that acts between them becomes 10 -19 N (a)25 (b)225 (c)625 (d)125 Please show the solution !!!!!!!!!!!!

(1) What is the excess number of electrons that must be placed on each of two small sphere spaced 3cm apart so that a force of repulsion that acts between them becomes 10-19N


(a)25


(b)225


(c)625


(d)125


Please show the solution !!!!!!!!!!!!

Grade:11

4 Answers

Abhishekh kumar sharma
34 Points
9 years ago

225

saurabh gupta
14 Points
9 years ago

here q1=q2

10-19=(9*109)(q1.q2)/32

10-28=q1q2

10-14C=q1

 

q=ne

10-14=n*1.6*10-19

n=625

BAYANA SAGAR
48 Points
9 years ago

I think that (c)is the correct answer.because no of electrons is 6.25( -18).10  

Mahendra Chapagain
13 Points
4 years ago
625
solution:
we know F=K.qq/r^2
applying in above question F=K.(ne)^2/r^2
Now N^2=F.r^2/(e^2.K) where k is constant value 8.98*10^9
finally by solving we get n=625
 

Think You Can Provide A Better Answer ?

Other Related Questions on Electrostatics

View all Questions »

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More