Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A charge Q is uniformly distributed over a long rod AB of length L . The electric potential at the point O lying at a distance L from the end A is: solve it by using the relation v=integration E.dr


A charge Q is uniformly distributed over a long rod AB of length L . The electric potential at the point O lying at a distance L from the end A is: 


solve it by using the relation v=integration E.dr


Grade:

1 Answers

Vikas TU
14149 Points
8 years ago

Let we take a small element of dq charge of dx length at a distance ''x'' from point O.  and then we will integrate it for potential of rod!

 

Thus, potential on a charge dq will be:

dV = Kdq/x = (kQ/l).dx/x

Integerating both sides from limits l to 0we get -

V = k(Q/l) [logl]

thus potential at point O comes  a constant value which is equals to:

V = k(Q/l) [logl].

 

 

Plz approve!

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free