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AT WHAT SEPARATION SHOULD TWO EQUAL CHARGES,1C EACH BE PLACED SO THAT THE FORCE BETWEEN THEM EQUALS THE WEIGHT OF A 50 Kg PERSON?
3*103√2 m
THE FORCE ON A 50KG PERSON DUE TO ACCELERATION DUE TO GRAVITY WILL BE F = mg ( that is also equal to the weight of the person)
so force = 50 x 10 = 500 N ( we have taken acc. due to gravity as 10 m/ s 2 )--------------(1)
and electrostatic force = q1 xq2 / 4 (pi) E0 r2 = 50 -------------(2)
USING THESE FORMULAS WE CAN FIND OUT THE VALUE OF r........ok...
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