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AT WHAT SEPARATION SHOULD TWO EQUAL CHARGES,1C EACH BE PLACED SO THAT THE FORCE BETWEEN THEM EQUALS THE WEIGHT OF A 50 Kg PERSON?

AT WHAT SEPARATION SHOULD TWO EQUAL CHARGES,1C EACH BE PLACED SO THAT THE FORCE BETWEEN THEM EQUALS THE WEIGHT OF A 50 Kg PERSON?


 

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2 Answers

eaishwary bajpai
18 Points
10 years ago

3*103√2 m

VISION TO SUCCESS
18 Points
10 years ago

THE FORCE ON A 50KG PERSON DUE TO ACCELERATION DUE TO GRAVITY WILL BE F = mg ( that is also equal to the weight of the person)

                 so force = 50 x 10 = 500 N  ( we have taken acc. due to gravity as 10 m/ s 2 )--------------(1)

                and electrostatic force = q1 xq2 / 4 (pi) E0 r2  = 50 -------------(2)

                USING THESE FORMULAS WE CAN FIND OUT THE VALUE OF r........ok...

 

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