AT WHAT SEPARATION SHOULD TWO EQUAL CHARGES,1C EACH BE PLACED SO THAT THE FORCE BETWEEN THEM EQUALS THE WEIGHT OF A 50 Kg PERSON?

3*10³√2 m

THE FORCE ON A 50KG PERSON DUE TO ACCELERATION DUE TO GRAVITY WILL BE F = mg ( that is also equal to the weight of the person)

                 so force = 50 x 10 = 500 N  ( we have taken acc. due to gravity as 10 m/ s ² )--------------(1)

                and electrostatic force = q1 xq2 / 4 (pi) E₀ r²  = 50 -------------(2)

                USING THESE FORMULAS WE CAN FIND OUT THE VALUE OF r........ok...