Four identical charges Q are fixed at the four corners of a square of side a. Show that the net electric field at a point P located symmetrically at a distance a / √2 from the centre of the square is Q / (√2 pie ε 0 a 2 ).

Question

Four identical charges Q are fixed at the four corners of a square of side a. Show that the net electric field at a point P located symmetrically at a distance a / &radic;2 from the centre of the square is Q / (&radic;2 pie &epsilon; 0 a 2 ).

Suraj Gurav · Answer

there r 4 charges at 4 corners of square... so by the formula of electric field E=Q/4 pie r 2 &epsilon; 0 . put values in this formula and multiply it by 4.u will get answer

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Four identical charges Q are fixed at the four corners of a square of side a. Show that the net electric field at a point P located symmetrically at a distance a / √2 from the centre of the square is Q / (√2 pie ε 0 a 2 ).

Four identical charges Q are fixed at the four corners of a square of side a. Show that the net electric field at a point P located symmetrically at a distance a / √2 from the centre of the square is Q / (√2 pie ε₀ a ² ).

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Four identical charges Q are fixed at the four corners of a square of side a. Show that the net electric field at a point P located symmetrically at a distance a / √2 from the centre of the square is Q / (√2 pie ε 0 a 2 ).

Four identical charges Q are fixed at the four corners of a square of side a. Show that the net electric field at a point P located symmetrically at a distance a / √2 from the centre of the square is Q / (√2 pie ε0 a 2 ).

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Four identical charges Q are fixed at the four corners of a square of side a. Show that the net electric field at a point P located symmetrically at a distance a / √2 from the centre of the square is Q / (√2 pie ε₀ a ² ).