Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A parallel plate capacitor C with plates of unit area and separation d is filled with a liquid of di-electric constant K=2. The level of the liquid is d/3 initially. Suppose the liquid level decreases at a constant speed V, the time constant as a function of time t is?
let level of liquid be 'h'. Capacitance Ceff =((C1*C2)/(C1+C2), where C1=(Ko/(d-h)) and C2=2/d,at t=0,h=d/3, C=∫(from h=d/3 to ((d/3)-vt))(dCeff/dt) dt dCeff/dt=(1/(C1+C2)2)((C1+C2)d(C1*C2)/dt -(C1*C2)d(C1+C2)/dt)
let level of liquid be 'h'. Capacitance Ceff =((C1*C2)/(C1+C2), where C1=(Ko/(d-h)) and C2=2/d,at t=0,h=d/3,
C=∫(from h=d/3 to ((d/3)-vt))(dCeff/dt) dt dCeff/dt=(1/(C1+C2)2)((C1+C2)d(C1*C2)/dt -(C1*C2)d(C1+C2)/dt)
Level of liquid = --t+d/3C1 =E/(vt+2d/3)C2=E/(-vt+d/3)Ceff=C1×C2/(C1+C2)Ceff=6E/(5d-3vt)T=R(Ceff)T=6ER/(5d-3vt)
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -