Q))Two equal chargs are ixed at x=a and x=-a on d axis.anodr pt charge Q is placed at d orign.The change in d electric potential energy of Q,when it is displaced by a small distance x along d x-axis, is approximately proportional to....(a)x(b)x2(c)x3(d)1/x

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Initial Energy:

K Qq/a

Final Energy

K qq*2a/(a*a-x*x)

Change in energy: Final energy-initial energy

= KQq [2*x*x/(a*a-x*x)a]

The x square term in the denominator can be neglected...So the change in energy is proportional to X square.

The corredc answer is (b)

Approved