when the current in a certain inductor coil is 5 A and is increasing at the rate of 10.0 A/s,the magnitude of potential difference acroos the coil is 140 V.when the current is 5.0 A and decreasing at the rate of 10.0 A/s,the potential difference is 60 V.the self inductance of the coil is

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AB is a current carrying conductor in the plane of the paper as shown in the figure below. (i) What is the direction of the magnetic field produced by it at point ‘X’? Write the statement of the rule used to find the direction of field lines. (ii) If the polarity of the battery connected to the wire is reversed, how would the direction of the magnetic field be changed? (iii) Point ‘X’ is at a distance r1 and point ‘Y’ is at a distance r2 (r1

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For minimum flux the angle between the magnetic field and normal to the surface is