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When the current changes from +2 A to – 2A in 0.05 second, and e.m.f. of 8 V is induced in a coil. The coefficient of self – induction of the coil is (a) 0.2 H (b) 0.4 H (c) 0.8 H (d) 0.1 H
(d) e = - ?Ø/?t ? 8 = L x 4/0.05 ? L = 8 x 0.05 / 4 = 0.1 H
(d) e = - ?Ø/?t ? 8 = L x 4/0.05
? L = 8 x 0.05 / 4 = 0.1 H
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