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What is repulsive Coulomb’s force between two protons in a nucleus of iron? Assume a separation of 4.0×10 -15 m . What is repulsive Coulomb’s force between two protons in a nucleus of iron? Assume a separation of 4.0×10-15 m.
As we knowF = 1/4(pi) q1*q2/r^2Q1 = 1.6 * 10 ^-19F = (9 x 109 Nm2/C2)(1.6 x 10-19 C)2 / (4.0 x10-15 m)2 = 14.375 N
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