Two long bar magnets are placed with their axes coinciding in such a way that the north pole of the first magnet is 2.0 cm from the south pole of the second. If both the magnets have a pole strength of 10 A-m, find the force exerted by one magnet on the other.
Amit Saxena , 10 Years ago
Grade upto college level
1 Answers
Navjyot Kalra
Last Activity: 10 Years ago
Sol. m base 1 =m base 2 = 10 A-m
r = 2 cm = 0.02 m
we know
force exerted by tow magnetic poles on each other = μ base 0/4π = m base 1m base 2/r^2 = 4π * 10^-7 *10^2/4π * 4 * 10^-4 = 2.5 * 10^-2 N
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