Two identical pith balls, each carrying a charge q, are suspended from a common point by two strings of equal length l, Find the mass of each ball if the angle between the strings is 2θ in equilibrium.

Question

Aditi Chauhan · Answer

Sol. Electric force = kq^2/(ℓ sin Q + ℓ sin Q)^2 = kq^2/4 ℓ^2 sin^2 So, T Cos θ = ms (For equilibrium) T sin θ = Ef Ef tan θ = Ef/mf ⇒ mg = Ef cot θ = kq^2/4ℓ^2 sin^2θ cot θ = q^2 cot θ/ℓ^2 sin^2θ 16πE base 0 Or m = q^2 cotθ/16πE base 0ℓ^2 Sin^2θg

Abhishek bains · Answer

F=mg tanxqq/16πEl^2 sin^2x tanx=m.......?........................... ............................................................. ............

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Two identical pith balls, each carrying a charge q, are suspended from a common point by two strings of equal length l, Find the mass of each ball if the angle between the strings is 2θ in equilibrium.

Two identical pith balls, each carrying a charge q, are suspended from a common point by two strings of equal length l, Find the mass of each ball if the angle between the strings is 2θ in equilibrium.

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Two identical pith balls, each carrying a charge q, are suspended from a common point by two strings of equal length l, Find the mass of each ball if the angle between the strings is 2θ in equilibrium.

Two identical pith balls, each carrying a charge q, are suspended from a common point by two strings of equal length l, Find the mass of each ball if the angle between the strings is 2θ in equilibrium.

2 Answers

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