Two equal charges are placed at a separation of 1.0 m. What should be the magnitude of the charges so that the force between them equals the weight of a 50 kg person?
Radhika Batra , 10 Years ago
Grade 11
2 Answers
Kevin Nash
Last Activity: 10 Years ago
Sol. charges ‘q’ each, AB = 1 m
Wt, of 50 kg person = 50 * g = 50 * 9.8 = 490 N
F base c = kq base 1q base 2/r^2 ∴ kq base 2/r^2 = 490 N
⇒ q^2 = 490 * r^2/9 * 10^9 = 490 * 1 * 1/9 * 10^9
⇒ q = √54.4 * 10^9 = 23.323 * 10^-5 coulomb = 2.3 * 10^-4 coulomb
Apoorva Arora
Last Activity: 10 Years ago
a 50 kg person exerts a force mg i.e 500 newtons
So,
so
so
Thanks and Regards
Apoorva Arora
IIT Roorkee
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