Two charged particles are placed at a distance 1.0 cm apart. What is the minimum possible magnitude of the electric force acting on each charge?
Simran Bhatia
12 Years agoGrade 11
4 Answers
Aditi Chauhan
12 Years ago
Sol. Minimum charge of a body is the charge of an electron
Wo, q = 1.6 × 10^–19 c x = 1 cm = 1 × 10^–2 cm
So, F = kq base 1q base 2/r^2 = 9 * 10^9 * 1.6 * 1.6 * 10^-19/10^-2 * 10^-2 = 23.04 * 10^-38+9+2+2 = 23.04 * 10^-25 = 2.3 * 10^-24
Apoorva Arora
12 Years ago
the distance is constant so force depends only on charge. so the force is minimum when charge is minimum i.e. charge of one electron.
So
putting all the values
F=
Thanks and Regards
Apoorva Arora
IIT Roorkee
askIITians Faculty
Anil sharma
9 Years ago
The charge q1 & q2 are placed at corner of square find q2 such that the resultant force on q1 is zero
Diksha
8 Years ago
F on q= vector of (F1+F2+F3)
0=F1+F2+F3(vector)
=kqQ/a^2(i+j)+kq^2/root2a^2 i+j/root2
0=kqQ/a^2+kqQ/2root2a^2
qQ+q^2/2root2=0. q= -2root2Q
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