Aditi Chauhan
Last Activity: 10 Years ago
Sol. (a) The power consumed by a coil of resistance R when connected across a supply v is P = v^2/R
The resistance of the heater coil is, therefore R = v^2/P = (250)^2/500 = 125 Ω
(b) If P = 1000 w then R = v^2/P = (250)^2/1000 = 62.5 Ω