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Grade: upto college level
        The potential difference between the terminals of a battery of emf 6.0 V and internal resistance 1 Ω drops to 5.8 V when connected across an external resistor. Find emf and the internal resistance of the battery.
5 years ago

Answers : (1)

Navjyot Kalra
askIITians Faculty
654 Points
							Sol. E = 6 V, r = 1 Ω, V = 5.8 V, R = ?
l = E/R + r = 6/R + 1, V = E – lr
⇒ 5.8 = 6 – 6/R + 1 * 1 ⇒ 6/R + 1 = 0.2
⇒ R + 1 = 30 ⇒ R = 29 Ω.

						
5 years ago
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