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Grade: upto college level
        Suppose all the electrons of 100 g water are lumped together to form a negatively charged particle and all the nuclei are lumped together to form a positively charged particle. If these two particle are placed 10.0 cm away from each other, find the force of attraction between them. Compare it with your weight.
5 years ago

Answers : (2)

Deepak Patra
askIITians Faculty
471 Points
							Sol. Molecular weight of H base 2O = 2 × 1 × 16 = 16
No. of electrons present in one molecule of H base 2O = 10
18 gm of H base 2O has 6.023 × 10^23 molecule
18 gm of H base 2O has 6.023 × 10^23 × 10 electrons
100 gm of H base 2O has 6.023 * 10^24/18 * 100 elecrons
So number of protons = 6.023 * 10^26/18 protons (since atom is electrically neutral)
Charge of protons = 1.6 * 10^-19 * 6.023 * 10^26/18 coulomb = 1.6 * 6.023 * 10^7/18 coulomb
Charge of electrons = = 1.6 * 6.023 * 10^7/18 coulomb
Hence Electrical force = 9 * 10^9(1.6 * 6.023 * 10^7/18)*( 1.6 * 6.023 * 10^7/18)/(10 * 10^-2)^2
= 8 * 6.023/18 * 1.6 * 6.023 * 10^25 = 2.56 * 10^25 Newton

						
5 years ago
maha
19 Points
							
Suppose all the electrons of 100 g water are lumped together to form a negatively charged particle and all the nuclei are lumped together to form a positively charged particle. If these two particle are placed 10.0 cm away from each other, find the force of attraction between them. Compare it with your weight.
2 years ago
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