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Ratio of gravitational force to the electrostatic force between one proton and one electron separated by certain distance is

Komal Meena , 6 Years ago
Grade 12
anser 1 Answers
Arun

Last Activity: 6 Years ago

Let R be the distance between the electron and the proton 

According to Newton's law of gravity the magnitude of the gravitational force between them is given by: 
Fg = G∙me∙mp/R² 

Electron as well as proton carry single elementary charge 
|q| = e = 1.602∙10⁻¹⁹C 
According to Coulomb's law the magnitude of electrostatic force between them is given by: 
Fg = k∙e²/R² 

Therefore 
Fe/Fg = (k∙e²/R²) / (G∙me∙mp/R²) 
= (k∙e²) / (G∙me∙mp) 
= (8.99∙10⁹Nm²/C² ∙ (1.602∙10⁻¹⁹C)² ) / ( 6.672∙10⁻¹¹Nm²/kg ∙ 9.109∙10⁻³¹kg ∙ 1.672∙10⁻²⁷kg ) 
= 2.27∙10³⁹

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