Flag Electromagnetic Induction> In a transformer, number of turns in the ...
question mark

In a transformer, number of turns in the primary coil are 140 and that in the secondary coil are 280. If current in primary coil is 4 A, then that in the secondary coil is
(a) 4 A
(b) 2 A
(c) 6 A
(d) 10 A.

lokesh , 10 Years ago
Grade 6
anser 2 Answers
Navjyot Kalra

Last Activity: 10 Years ago

(b) Np = 140 , Ns = 280, Ip = 4A, Is = ?

For a transformer Is / Ip =NP / Ns

? Is /4 = 140 / 250 ? Is = 2A

Vasantha Kumari

Last Activity: 10 Years ago

We know that for a transformer I1N1 = I2N2 where I1 and I2 are the currents through the coil and N1 = N2 are the number of turns in the primary and secondary coils.

Therefore, I2 = I1N1/ N2

=4 x 140 / 280

= 2A

Thanks & Regards,

Vasantha Sivaraj,

askIITians faculty

Provide a better Answer & Earn Cool Goodies

star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free