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In a transformer, number of turns in the primary coil are 140 and that in the secondary coil are 280. If current in primary coil is 4 A, then that in the secondary coil is(a) 4 A(b) 2 A(c) 6 A(d) 10 A.
(b) Np = 140 , Ns = 280, Ip = 4A, Is = ? For a transformer Is / Ip =NP / Ns ? Is /4 = 140 / 250 ? Is = 2A
(b) Np = 140 , Ns = 280, Ip = 4A, Is = ?
For a transformer Is / Ip =NP / Ns
? Is /4 = 140 / 250 ? Is = 2A
We know that for a transformer I1N1 = I2N2 where I1 and I2 are the currents through the coil and N1 = N2 are the number of turns in the primary and secondary coils. Therefore, I2 = I1N1/ N2 =4 x 140 / 280 = 2A Thanks & Regards, Vasantha Sivaraj, askIITians faculty
We know that for a transformer I1N1 = I2N2 where I1 and I2 are the currents through the coil and N1 = N2 are the number of turns in the primary and secondary coils.
Therefore, I2 = I1N1/ N2
=4 x 140 / 280
= 2A
Thanks & Regards,
Vasantha Sivaraj,
askIITians faculty
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