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(b) Np = 140 , Ns = 280, Ip = 4A, Is = ?
For a transformer Is / Ip =NP / Ns
? Is /4 = 140 / 250 ? Is = 2A
We know that for a transformer I1N1 = I2N2 where I1 and I2 are the currents through the coil and N1 = N2 are the number of turns in the primary and secondary coils.
Therefore, I2 = I1N1/ N2
=4 x 140 / 280
= 2A
Thanks & Regards,
Vasantha Sivaraj,
askIITians faculty
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