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Grade: 12th pass
        
for given question correct answer is option 2. please explain.
one year ago

Answers : (2)

Arun
24735 Points
							
B1 dies out promptly but B2 with some delay because of presence of inductance in its circuit.
 
hence I think answer should be option 3
one year ago
Sanjai
50 Points
							
Yes even I think the answer should be 3. Because when the switch is closed the bulb 💡 b1 would light up early but do to infinite resistance from the inductor the bulb b2 would light late. Similarly when the switch is off the bubl b1 dies out immediately as there is no supply but now the inductor can act as a battery until it dies out of charges. So ultimately the bulb b2 would die a bit late.
11 months ago
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