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Grade: 12th pass
        
find the induced emf in a 0.50-m rod moving with velocity of 2 m/sec perpendicular to a field of 2x10-4 Wb/m^2, or tesla.
 
6 months ago

Answers : (2)

Samyak Jain
333 Points
							
We know that induced emf in a rod of length L is BvL, where magnetic field B, velocity v and
length of rod are mutually perpendicular.
Induced emf E = BvL = (2 x 10 – 4)(2)(0.50) = 2 x 10 – 4 volt.
6 months ago
Khimraj
3008 Points
							
E = BvL = (2 x 10 – 4)(2)(0.50) = 2 x 10 – 4 volt.
..................................................................................
4 months ago
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