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find the induced emf in a 0.50-m rod moving with velocity of 2 m/sec perpendicular to a field of 2x10-4 Wb/m^2, or tesla.

aina , 6 Years ago
Grade 12th pass
anser 2 Answers
Samyak Jain
We know that induced emf in a rod of length L is BvL, where magnetic field B, velocity v and
length of rod are mutually perpendicular.
Induced emf E = BvL = (2 x 10 – 4)(2)(0.50) = 2 x 10 – 4 volt.
ApprovedApproved
Last Activity: 6 Years ago
Khimraj
E = BvL = (2 x 10 – 4)(2)(0.50) = 2 x 10 – 4 volt.
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Last Activity: 6 Years ago
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