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Grade 12th passElectromagnetic Induction

find the induced emf in a 0.50-m rod moving with velocity of 2 m/sec perpendicular to a field of 2x10-4 Wb/m^2, or tesla.

Profile image of aina
7 Years agoGrade 12th pass
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2 Answers

Profile image of Samyak Jain
ApprovedApproved Tutor Answer7 Years ago
We know that induced emf in a rod of length L is BvL, where magnetic field B, velocity v and
length of rod are mutually perpendicular.
Induced emf E = BvL = (2 x 10 – 4)(2)(0.50) = 2 x 10 – 4 volt.
Profile image of Khimraj
7 Years ago
E = BvL = (2 x 10 – 4)(2)(0.50) = 2 x 10 – 4 volt.
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