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Grade: 11
        Find the dimensional formula of ε0. 
4 years ago

Answers : (3)

Aditi Chauhan
askIITians Faculty
396 Points
							Sol. ε base 0 = Coulomb^2/Newton m^2 = l^1 M^-1 L^-3 T^4
∴ F = kq base 1q base 2/r^2

						
4 years ago
Apoorva Arora
IIT Roorkee
askIITians Faculty
181 Points
							
The permittivity of free space is given by
\epsilon _{0}=8.85\times 10^{-12} m^{-3} Kg^{-1}s^{4}A^{2}
so the dimensional formula is
=[M^{-1}L^{-3}T^{4}A^{2}]
Thanks and Regards
Apoorva Arora
IIT Roorkee
askIITians Faculty
4 years ago
Apoorva Arora
IIT Roorkee
askIITians Faculty
181 Points
							
The permittivity of free space is given by
Description: \epsilon _{0}=8.85\times 10^{-12} m^{-3} Kg^{-1}s^{4}A^{2}
so the dimensional formula is
Description: =[M^{-1}L^{-3}T^{4}A^{2}]
Thanks and Regards
Apoorva Arora
IIT Roorkee
askIITians Faculty
4 years ago
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