Navjyot Kalra
Last Activity: 11 Years ago
Sol. No. of electrons of 100g water = 10 * 100/18 = 55.5 Nos total charge = 55.5
No. of electrons in 18 g of H base 2O = 6.023 * 10^23 * 10 = 6.023 * 10^24
No. of electrons in 100 g of H base 2O = 6.023 * 24^24 * 100/18 = 0.334 * 10^26 = 3.334 * 10^25
Total charge = 3.34 * 10^25 * 1.6 * 10^-19 = 5.34 * 10^6 c
