Jitender Pal
Last Activity: 10 Years ago
Sol. Initial pressure = P base 0
Initial Volume = V base 0
γ = C base P/C base V
(a) Isothermally to pressure P base 0/2
P base 0V base 0 = P base 0/2 V base 1 = 2 V base 0
Adiabatically to pressure = P base 0/4
P base 0/2 (V base 1)^γ = P base 0/4 (V base 2)^γ ⇒ P base 0/2 (2V base 0)^γ = P base 0/4 (V base 2)^γ
⇒ 2^γ+1 V base 0^γ = V base 2^γ ⇒ V base 2 = 2^(γ+1)/γ V base 0
∴ Final Volume = 2^(γ+1)/γ V base 0
(b) Adiabetically to pressure P base 0/2 * (V’)γ
P base 0 * (2^γ+1 V base 0^γ) = P base 0/2 * (V’)γ
Isothermal to pressure P base 0/4
P base 0/2 * 2^1/γ V base 0 = P base 0/4 * V” ⇒ V” = 2^(γ+1)/γ V base 0
∴ Final Volume = 2^(γ+1)/γ V base 0