Aditi Chauhan
Last Activity: 11 Years ago
Sol.
f = 8.52 x 10 ^28 atoms / m^3
For maximum ‘I’, Let us consider the no. of atoms present in 1 m^3 of volume.
Given: m per atom = 2 × 9.27 × 10^–24 A–m^2
I = net m / V = 2 × 9.27 × 10^–24 × 8.52 × 10^28 ≈ 1.58 × 10^6 A/m
B = μ0 (H + I) = μ0 [∴ H = 0 in this case]
= 4π × 10^–7 × 1.58 × 10^6 = 1.98 × 10^–1 ≈ 2.0 T