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An immersion heater rated 1000 W, 220 V is used to heat 0.01 m^3 of water. Assuming that the power is supplied at 220 V and 60% of the power supplied is used to heat the water, how long will it take to increase the temperature of the water from 15°C to 40°C?

An immersion heater rated 1000 W, 220 V is used to heat 0.01 m^3 of water. Assuming that the power is supplied at 220 V and 60% of the power supplied is used to heat the water, how long will it take to increase the temperature of the water from 15°C to 40°C?

Grade:11

1 Answers

Aditi Chauhan
askIITians Faculty 396 Points
6 years ago
Sol. P = 1000 V = 220 v R = V^2/P = 48400/1000 = 48.4 Ω Mass of water = 1/100 * 1000 = 10 kg Heat required to raise the temp. of given amount of water = ms∆t = 10 * 4200 * 25 = 1050000 Now heat liberated is only 60%. So V^2/R =T=60% = 1050000 ⇒ (220)^2/48.4 * 60/100 * T = 1050000 ⇒ T = 10500/6 * 1/60 nub = 29.16 min.

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