An ideal coil of 10 H is connected in a series with a resistance of 5 Ω and bettery of 5 V. Two second after the connection is made, the current flowing in amperes in the circuit is (a) e (b) e^-1 © (1- e^-1) (d) (1-e)

Question

An ideal coil of 10 H is connected in a series with a resistance of 5 Ω and bettery of 5 V. Two second after the connection is made, the current flowing in amperes in the circuit is (a) e (b) e^-1 © (1- e^-1) (d) (1-e)

jakira · Answer

I = I 0 [ 1 − e − R t / L ] I = I 0 I 0 [1-e -Rt/L ] I0 = 5/5=1 So I = 1-e -5t/10 i.e I = 1-e -t/2 As t=2, So I =1-e -1 I = I 0 [ 1 − e − R t / L ]

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An ideal coil of 10 H is connected in a series with a resistance of 5 Ω and bettery of 5 V. Two second after the connection is made, the current flowing in amperes in the circuit is (a) e (b) e^-1 © (1- e^-1) (d) (1-e)

An ideal coil of 10 H is connected in a series with a resistance of 5 Ω and bettery of 5 V. Two second after the connection is made, the current flowing in amperes in the circuit is
(a) e (b) e^-1 © (1- e^-1) (d) (1-e)

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An ideal coil of 10 H is connected in a series with a resistance of 5 Ω and bettery of 5 V. Two second after the connection is made, the current flowing in amperes in the circuit is (a) e (b) e^-1 © (1- e^-1) (d) (1-e)

An ideal coil of 10 H is connected in a series with a resistance of 5 Ω and bettery of 5 V. Two second after the connection is made, the current flowing in amperes in the circuit is(a) e (b) e^-1 © (1- e^-1) (d) (1-e)

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An ideal coil of 10 H is connected in a series with a resistance of 5 Ω and bettery of 5 V. Two second after the connection is made, the current flowing in amperes in the circuit is
(a) e (b) e^-1 © (1- e^-1) (d) (1-e)