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Grade: upto college level
         An ideal battery sends a current of 5 A in a resistor. When another resistor of value 10 Ω is connected in parallel, the current through the battery is increased to 6 A. Find the resistance of the first resistor.
5 years ago

Answers : (1)

Navjyot Kalra
askIITians Faculty
654 Points
							Sol. R base 1 = R, i base 1 = 5 A
R base 2 = 10R/10 + R, i base 2 = 6A
Since potential constant,
i base 1R base 1 = i base 2R base 2
⇒ 5 * R = 6 * 10R/10 + R
⇒ (10 + R)5 = 60
⇒ 5R = 10 ⇒ R = 2 Ω

						
5 years ago
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