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An alternating emf is given by e=100sin 314t,the time within which the emf will be half of its maximum value is

Khan faaz , 6 Years ago
Grade 12
anser 1 Answers
Arun

Last Activity: 6 Years ago

Dear Khan
 
for half emf
 
sin 314t = ½
 
sin 100 * pi * t = ½
 
100 * pi * t = pi / 6
 
t = 1/600 sec
 
Hope it helps
Regards
Arun

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