MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12
        
An air coref solenoid is of length 0.3 m , cross section area 1.2* 10-3 m2    nn hhahashas 2500 turns Around its central section a coil of 350 turns is wound The solenoid and the coil are electrically jnsulated from each other calculate the emf induced in the coil if the initial of 3A in the solenoid is reversed in 0.25 s 
 
one year ago

Answers : (1)

Eshan
askIITians Faculty
2095 Points
							Dear student,

Magnetic field inside the solenoid intially=\mu_0nI.
Hence flux inside the solenoid=\mu_0nIA

After reversing the current, the direction of magnetic field also reverses. Hence change in magnetic field=\Delta B=2\mu_0nI.
The whole solenoid lies inside the coil and hence the magnetic flux inside the coil is ‘N’ timesthat inside solenoid.
Hence EMF induced in coil=\dfrac{\Delta \phi}{\Delta t}=\dfrac{2A\Delta B}{\Delta t}=\dfrac{2\mu_0NnI}{\Delta t}\dfrac{\Delta \phi}{\Delta t}=\dfrac{2AN\Delta B}{\Delta t}=\dfrac{2A\mu_0NnI}{\Delta t}
one year ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 57 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details