Air (γ = 1.4) is pumped at 2 atm pressure in a motor tyre at 20C. If the tyre suddenly bursts, what would be the temperature of the air coming out of the tyre. Neglect any mixing with the atmospheric air.
Radhika Batra
12 Years agoGrade 11
2 Answers
Navjyot Kalra
12 Years ago
Sol. γ = 1.4, T base 1 = 20°C = 293 k, P base 1 = 2 atm, p base 2 = 1 atm
We know for adiabatic process,
P base 1^1-γ * T base 1^γ = P base 2^1-γ * T base 2^γ or (2)^1-1.4 * (293)^1.4 = (1)^1-1.4 * T base 2^1.4
⇒ (2)^0.4 * (293)^1.4 = T base 2^1.4 ⇒ 2153.78 = T base^1.4 ⇒ T base 2 = (2153.78)^1/1.4 = 240.3 K
Jitender Pal
12 Years ago
Sol. Sol. γ = 1.4, T base 1 = 20°C = 293 k, P base 1 = 2 atm, p base 2 = 1 atm
We know for adiabatic process,
P base 1^1-γ * T base 1^γ = P base 2^1-γ * T base 2^γ or (2)^1-1.4 * (293)^1.4 = (1)^1-1.4 * T base 2^1.4
⇒ (2)^0.4 * (293)^1.4 = T base 2^1.4 ⇒ 2153.78 = T base^1.4 ⇒ T base 2 = (2153.78)^1/1.4 = 240.3 K
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