# A vertical rod of length l is moved with constant velocity v towards east. The vertical component of earth magnetic field is B and angle of dip is theta. What is the induced emf in the rod?

Ritik
19 Points
5 years ago
Induced EMF is given by E= Blv ......1 Vertical component of B is B sin theta From 1 ,we getE= (B sin theta)× L× v cos theta E= B/v cot theta
1234567890
15 Points
4 years ago
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ankit singh
2 years ago
A vertical conducting rod of length l is moved at a constant velocity v eastward. The vertical component of the Earth's magnetic field is B and the angle of dip is theta. ... The rod is vertical and moves east ward, therefore it 'cuts' horizontal component Bh of the magnetic field.
Naman Agrawal
13 Points
one year ago

## From the above figure, are conclude that magnetic force which is responsible for induction of emf is horizontal component of magnetic field only.

Formula Δe=(Vˉ×Bˉ)l=VBlsin90=VBl

Now tanθ=BBHBH=Bcotθ

Now, emf induced =
e=V(BHl)

e=VBlcotθ

e=Blvcotθ