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A vertical rod of length l is moved with constant velocity v towards east. The vertical component of earth magnetic field is B and angle of dip is theta. What is the induced emf in the rod?

Vatsala , 8 Years ago

Grade 12th pass

4 Answers

Ritik

Last Activity: 7 Years ago

Induced EMF is given by E= Blv ......1 Vertical component of B is B sin theta From 1 ,we getE= (B sin theta)× L× v cos theta E= B/v cot theta

1234567890

Last Activity: 6 Years ago

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ankit singh

Last Activity: 4 Years ago

A vertical conducting rod of length l is moved at a constant velocity v eastward. The vertical component of the Earth's magnetic field is B and the angle of dip is theta. ... The rod is vertical and moves east ward, therefore it 'cuts' horizontal component Bh of the magnetic field.

Naman Agrawal

Last Activity: 3 Years ago

From the above figure, are conclude that magnetic force which is responsible for induction of emf is horizontal component of magnetic field only.

Formula Δe=(Vˉ×Bˉ)l=VBlsin90∘=VBl

Now tanθ=BBH⇒BH=Bcotθ

Now, emf induced =

e=V(BHl)

e=VBlcotθ

⇒e=Blvcotθ

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