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Grade 6Electromagnetic Induction

. A uniformly wound solenoidal coil of self inductance 1.8 x 10-4 henry and resistance 6 ohm is broken up into two identical coils. These identical coils are then connected in parallel across a 15-volt battery of negligible resistance. The time constant for the current in the circuit is …….. seconds and the steady state current through the battery is ……… amperes.

Profile image of lokesh
12 Years agoGrade 6
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1 Answer

Profile image of Navjyot Kalra
12 Years ago

The coil is broken into two identical coils.

Leq = L / 2 X L / 2 / L / 2 + L / 2 = L/4 = 0.45 X 10-4 H,

= R / 2 X R / 2 / R / 2 + R / 2 = R / 4 = 1.5 O

Time constant = Leq / Req = 0.45 x 10-4 / 1.5 = 0.3 x 10-4 s

Steady current I = E / Req = 15/ 1.5 = 10 A.