MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
lokesh Grade: 6
        
. A uniformly wound solenoidal coil of self inductance 1.8 x 10-4 henry and resistance 6 ohm is broken up into two identical coils. These identical coils are then connected in parallel across  a 15-volt battery of negligible resistance. The time constant for the current in the circuit is …….. seconds and the steady state current through the battery is ……… amperes.
3 years ago

Answers : (1)

Navjyot Kalra
askIITians Faculty
654 Points
										

The coil is broken into two identical coils.

Leq = L / 2 X L / 2 / L / 2 + L / 2 = L/4 = 0.45 X 10-4 H,

= R / 2 X R / 2 / R / 2 + R / 2 = R / 4 = 1.5 O

Time constant = Leq / Req = 0.45 x 10-4 / 1.5 = 0.3 x 10-4 s

Steady current I = E / Req = 15/ 1.5 = 10 A.

3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details
  • Electricity and Magnetism
  • OFFERED PRICE: Rs. 1,696
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details