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Grade: 11
        A uniform wire of resistance 100 Ω is melted and recast in a wire of length double that of the original. What would be the resistance of the wire?
4 years ago

Answers : (1)

Navjyot Kalra
askIITians Faculty
654 Points
							Sol. ℓ ‘ = 2 ℓ
volume of the wire remains constant.
A ℓ = A’ ℓ ‘
⇒ A ℓ = A’ * 2 ℓ
⇒ A’ = A/2
f = Specific resistance
R = fℓ/A : R’ = fℓ’/A’
100 Ω = f2ℓ/A / 2 = 4fℓ/A = 4R
⇒ 4 * 100 Ω = 400 Ω

						
4 years ago
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