Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A thin flexible wire of length L is connected to two adjacent fixed points and the wire carries a current I in the clockwise direction. When the system is put in a uniform magnetic field with a strength of B going into the plane of the paper, the wire takes the shape of a circle. The tension in the wire is?

A thin flexible wire of length L is connected to two adjacent fixed points and the wire carries a current I in the clockwise direction. When the system is put in a uniform magnetic field with a strength of B going into the plane of the paper, the wire takes the shape of a circle. The tension in the wire is?

Grade:

1 Answers

Arun
25763 Points
2 years ago
Dear student
 
you have not attached an image.
 
but I remember that similiar question has been asked in IIT in 2010 or 2011.
 
So I am answering it from that context.
 
Considering an elemental length dL of the wire, the magnetic force F acting on the element is given by
 
idLB = iRdθB, as is clear from the figure.
 
The tension developed in the wire is resolved into rectangular components T sin(dθ/2) and Tcos(dθ/2) as indicated in the figure.
 
The magnetic force is related to the tension T as
 
iRdθB = 2T sin(dθ/2)
 
Since  is a very small angle, sin(dθ/2) ≈ dθ/2
 
Therefore, the above equation gives T = iRB
 
But R = L /
 
Therefore, T = iBL /

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free