Navjyot Kalra
Last Activity: 11 Years ago
Sol. T = 2π√I/MB base H Here I’ = 2I
T base 1 = 1/40 min T base 2 = ?
T base 1/T base 2 = √I/I’
⇒ 1/40T base 2 = √1/2 ⇒ 1/1600T base 2^2 = 1/2 ⇒ T base 2^2 = 1/800 ⇒ T base 2 = 0.03536 min
For 1 oscillation Time taken = 0.03536 min.
For 40 Oscillation Time = 4 * 0.03536 = 1.414 = √2 min