Flag Electromagnetic Induction> A short magnet oscillates in an oscillati...
question mark

A short magnet oscillates in an oscillation magnetometer with a time period of 0.10 s where the earth’s horizontal magnetic field is 24 μT. A downward current of 18 A is established in a vertical wire placed 20 cm east of the magnet. Find the new time period.

Amit Saxena , 11 Years ago
Grade upto college level
anser 1 Answers
Navjyot Kalra

Last Activity: 11 Years ago

Sol. T = 2π√I/MB base H Here I’ = 2I T base 1 = 1/40 min T base 2 = ? T base 1/T base 2 = √I/I’ ⇒ 1/40T base 2 = √1/2 ⇒ 1/1600T base 2^2 = 1/2 ⇒ T base 2^2 = 1/800 ⇒ T base 2 = 0.03536 min For 1 oscillation Time taken = 0.03536 min. For 40 Oscillation Time = 4 * 0.03536 = 1.414 = √2 min
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments