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`        a q charge is distributed over two concentric spherical shells of radius r and R (R>r) and having same surface charge densities . find the potential at the common centre of the shell `
one year ago

```							 By superposition princpiple, potential at the common centre is equal to algebraic sum of potentials at centre due to each sphere. If we want the potential of a sphere, we need the radius (given) and the charge on it (which is what we should find now).If the total charge is Q, then let’s assume charge of small sphere si q1, and large sphere is q2.Thus  It is given that the surface charge density is the same, thus:Therefore, But therefore,and similarly (from the same equation,Potential at common centre is now given as: Substituting previously found values, this becomes: RegardsArun
```
one year ago
```							charge density=q/4(3.14)r=Q/4(3.14)R.ie, q=Q*r*r/R*R.potential at center of shell=kq/r+kQ/RkQ/R(r/R+1)Q=charge density*4(3.14)R*Ron simpilfying,V=charge density*(r+R)/epsilon
```
one year ago
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