Flag Electromagnetic Induction> A proton is projected with a velocity of ...
question mark

A proton is projected with a velocity of 3 × 10^6 m/s perpendicular to a uniform magnetic field of 0.6 T. Find the acceleration of the proton.

Simran Bhatia , 10 Years ago
Grade 11
anser 1 Answers
Aditi Chauhan

Last Activity: 10 Years ago

Sol. υ = 3 × 10^6 m/s, B = 0.6 T, m = 1.67 × 10^–27 kg F = qυB q base P = 1.6 × 10^–19 C Or, a ⃗ = F/m = qυB/m = 1.6 * 10^-19 * 3 * 10^6 * 10^-1/1.67 * 10^-27 = 17.245 * 10^13 = 1.724 * 10^4 m/s^2

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...