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Grade: 11
        A proton is projected with a velocity of 3 × 10^6 m/s perpendicular to a uniform magnetic field of 0.6 T. Find the acceleration of the proton.
4 years ago

Answers : (1)

Aditi Chauhan
askIITians Faculty
396 Points
							Sol. υ = 3 × 10^6 m/s, B = 0.6 T, m = 1.67 × 10^–27 kg
F = qυB q base P = 1.6 × 10^–19 C
Or, a ⃗ = F/m = qυB/m
= 1.6 * 10^-19 * 3 * 10^6 * 10^-1/1.67 * 10^-27
= 17.245 * 10^13 = 1.724 * 10^4 m/s^2

						
4 years ago
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