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akash Grade: 12
        A particle of mass M having a charge q enters into a circular region of radius R with a velocity v directed towards the centre. The strength of magnetic field is B. Find angle deviation in the path of the particle. B is directed into the circular region
one year ago

Answers : (1)

GAGANDEEP SINGH
46 Points
										My approach:The radius of the circular path take by the charge will be mv/qB. Now you have to find out the slope of the tangent to the circular path of the charge at the point of intersection of the path with the circular region. If it comes out to be negative then add 180° to it otherwise not. There can also be other faster solutions. Please tell if anybody has.
										
one year ago
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