Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A particle having a charge of 2.0 × 10^-8 C and a mass of 2.0 × 10^-10 g is projected with a speed of 2.0 × 10^3 m/s. in a region having a uniform magnetic field of 0.10 T. The velocity is perpendicular to the field. Find the radius of the circle formed by the particle and also the time period.

A particle having a charge of 2.0 × 10^-8 C and a mass of 2.0 × 10^-10 g is projected with a speed of 2.0 × 10^3 m/s. in a region having a uniform magnetic field of 0.10 T. The velocity is perpendicular to the field. Find the radius of the circle formed by the particle and also the time period.

Grade:upto college level

1 Answers

Navjyot Kalra
askIITians Faculty 654 Points
7 years ago
Sol. q = 2.0 × 10–8 C B ⃗ = 0.10 T m = 2.0 * 10^-10 g = 2 * 10^-13 g υ = 2.0 * 10^3 m/’ R = m υ/qB = 2 * 10^-13 *2 * 10^3/2 * 10^-8 * 10^-1 = 0.2 m = 20 cm T = 2πm/qB = 2 * 3.14 *2 * 10^-13/2 * 10^-18 * 10^-1 = 6.28 * 10^-4 s

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free