Flag Electromagnetic Induction> A parallel-plate capacitor with the plate...
question mark

A parallel-plate capacitor with the plate area 100 cm^2 and the separation between the plates 1.0 cm is connected across a battery of emf 24 volts. Find the force of attraction between the plates.

Radhika Batra , 10 Years ago
Grade 11
anser 1 Answers
Aditi Chauhan

Last Activity: 10 Years ago

Sol. A = 100 cm2 = 10^–2 m^2 d = 1 cm = 10^–2 m V = 24 V base 0 ∴ The capacitance C = ε base 0A/d = 8.85 * 10^-12 * 10^-2/10^-2 = 8.85 * 10^-12 ∴ The energy stored C base 1 = (1/2) CV^2 = (1/2) × 10^–12 × (24)^2 = 2548.8 × 10^–12 ∴ The forced attraction between the plates = C base 1/d = 2548.8 * 10^-12/10^-2 = 2.54 * 10^-7 N.

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...