Navjyot Kalra
Last Activity: 10 Years ago
Sol. Cp’ = 2.5 RCp” = 3.5 R
Cv’ = 1.5 R Cv” = 2.5 R
n base 1 = n base 2 = 1 mol (n base 1 + n base 2)CVdT = n base 1 C base vdT + n base 2 C base vdT
⇒ Cv = n base 1Cv’+ n base 2 Cv”/n base 1 + n base 2 = 1.5R + 2.5R/2 2R
C base P = C base V + R = 2R + R = 3R
γ = C base p/C base V = 3R/2R = 1.55