A magnetic flux of 8 × 10^-4 weber is linked with each turn of a 200-turn coil when there is an electric current of 4 A in it. Calculate the self-inductance of the coil.

Question

Deepak Patra · Answer

Sol. dϕ/dt = 8 x 10^-4 weber n = 200, l = 4A, E = -nL dl/dt or, -dϕ/dt = -Ldl/dt or, L = n dϕ/dt = 200x8x10-4 = 2 x 10^-2 H.

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A magnetic flux of 8 × 10^-4 weber is linked with each turn of a 200-turn coil when there is an electric current of 4 A in it. Calculate the self-inductance of the coil.

A magnetic flux of 8 × 10^-4 weber is linked with each turn of a 200-turn coil when there is an electric current of 4 A in it. Calculate the self-inductance of the coil.

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A magnetic flux of 8 × 10^-4 weber is linked with each turn of a 200-turn coil when there is an electric current of 4 A in it. Calculate the self-inductance of the coil.

A magnetic flux of 8 × 10^-4 weber is linked with each turn of a 200-turn coil when there is an electric current of 4 A in it. Calculate the self-inductance of the coil.

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