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Grade: 10
        A deflection magnetometer is placed with its arms in north-south direction. How and where should a short magnet having M/B baseH = 40 A-m^2/T be placed so that the needle can stay in any position?
4 years ago

Answers : (1)

Jitender Pal
askIITians Faculty
365 Points
							Sol. According to oscillation magnetometer,
T = 2π√I/MB base H
⇒ π/10 = 2π√1.2 * 10^-4/M * 30 * 10^-6
⇒ (1/20)^2 = 1.2 * 10^-4/M * 30 * 10^-6
⇒ M = 1.2 *10^-4 *400/30 * 10^-6 = 16 * 10^2 A-m^2 = 1600 A-m^2

						
4 years ago
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