A coil of resistance 100 Ω is connected across a battery of emf 6.0 V. Assume that the heat developed in the coil is used to raise it temperature. If the heat capacity of the coil is 4.0 J/K, how long will it take to raise the temperature of the coil by 15°C?

Question

Jitender Pal · Answer

Sol. R = 100 Ω, Heat capacity of the coil = 4 J/k ∆T = 15°c Heat liberate ⇒ E^2/RT = 4 J/K * 15 ⇒ 6 * 6/100 *t = 60 ⇒ t = 166.67 sec = 2.8 min

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A coil of resistance 100 Ω is connected across a battery of emf 6.0 V. Assume that the heat developed in the coil is used to raise it temperature. If the heat capacity of the coil is 4.0 J/K, how long will it take to raise the temperature of the coil by 15°C?

A coil of resistance 100 Ω is connected across a battery of emf 6.0 V. Assume that the heat developed in the coil is used to raise it temperature. If the heat capacity of the coil is 4.0 J/K, how long will it take to raise the temperature of the coil by 15°C?

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A coil of resistance 100 Ω is connected across a battery of emf 6.0 V. Assume that the heat developed in the coil is used to raise it temperature. If the heat capacity of the coil is 4.0 J/K, how long will it take to raise the temperature of the coil by 15°C?

A coil of resistance 100 Ω is connected across a battery of emf 6.0 V. Assume that the heat developed in the coil is used to raise it temperature. If the heat capacity of the coil is 4.0 J/K, how long will it take to raise the temperature of the coil by 15°C?

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