Aditi Chauhan
Last Activity: 10 Years ago
Q = –2.0 × 10–6C Surface charge density = 4 × 10–6 C/m2
We know □(→┬E ) due to a charge conducting sheet = σ/2ε base 0
Again Force of attraction between particle & plate
= Eq = σ/2ε base 0 * q = 4 * 10^-6 * 2 * 10^-6/2 * 8 * 10^-12 = 0.452N